Here is an article on how to create a simple calculator program using a switch case statement in C:

Creating a Calculator Program in C using a Switch case Statement

Calculator programs are a common project for beginners to learn a programming language. In this article, we will create a simple calculator program in C using a switch case statement.

To begin, we will first need to include the stdio.h header file, which provides functions for input and output in C.

Next, we will define the main function where the program will start execution. Inside the main function, we will declare variables for the operator and operands. We will use a char type for the operator and double types for the operands.

int main() { char operator; double firstNumber, secondNumber;

Next, we will prompt the user to enter an operator by using the printf function and then use the scanf function to read the operator entered by the user.

printf("Enter an operator (+, -, *, /): ");
scanf("%c", &operator);

Then, we will prompt the user to enter two operands and read them using the scanf function.

printf("Enter two operands: ");
scanf("%lf %lf", &firstNumber, &secondNumber);

Now, we will use a switch statement to perform the corresponding operation based on the operator entered by the user. The switch statement will have cases for each of the four possible operators: +, -, *, and /. For each case, we will use the printf function to print the result of the operation.

switch(operator) {
case '+':
printf("%.1lf + %.1lf = %.1lf", firstNumber, secondNumber, firstNumber + secondNumber);
break;
case '-':
printf("%.1lf - %.1lf = %.1lf", firstNumber, secondNumber, firstNumber - secondNumber);
break;
case '*':
printf("%.1lf * %.1lf = %.1lf", firstNumber, secondNumber, firstNumber * secondNumber);
break;
case '/':
printf("%.1lf / %.1lf = %.1lf", firstNumber, secondNumber, firstNumber / secondNumber);
break;

Finally, we will include a default case for when the operator entered by the user does not match any of the cases. This will handle any invalid input by the user.

// operator doesn't match any case default: printf("Error! operator is not correct"); }

To finish the program, we will return 0 from the main function to indicate that the program has successfully completed.

return 0; }

Here is an example of a simple calculator program using a switch case statement in C:

#include
int main() {
char operator;
double firstNumber, secondNumber;
printf("Enter an operator (+, -, *, /): ");
scanf("%c", &operator);
printf("Enter two operands: ");
scanf("%lf %lf", &firstNumber, &secondNumber);
switch(operator) {
case '+':
printf("%.1lf + %.1lf = %.1lf", firstNumber, secondNumber, firstNumber + secondNumber);
break;
case '-':
printf("%.1lf - %.1lf = %.1lf", firstNumber, secondNumber, firstNumber - secondNumber);
break;
case '*':
printf("%.1lf * %.1lf = %.1lf", firstNumber, secondNumber, firstNumber * secondNumber);
break;
case '/':
printf("%.1lf / %.1lf = %.1lf", firstNumber, secondNumber, firstNumber / secondNumber);
break;
//operator doesnt match any case
default:
printf("Error! operator is not correct");
}
return 0;
}
;